Andrew Bogut
Born in 1984, Andrew Bogut is 41 as of October 2026. This center from Australia is listed at 213 cm (7 ft 0 in). Quick facts, a few common questions and similar players follow, so you can size up his profile at a glance.
His college program was University of Utah. The teams on his record, oldest first, are Milwaukee Bucks, Golden State Warriors, Dallas Mavericks and Cleveland Cavaliers. The latest stint on record is with Cleveland Cavaliers. The dated stints in his record cover 2005–2017.
Andrew Bogut is taller than 43% of the 62 centers in Hardwood's player pool. University of Utah also produced two other players in Hardwood's pool. He is one of 8 players from Australia in the pool. For scale, the average height across all 513 players in the pool is 201 cm, so he stands 12 cm above it. Everything here is drawn from Wikidata, which means the teams and dates reflect the public record, not a full game-by-game history.
Can you guess them in Hardwood's daily puzzle?
QUICK FACTS
| Position | Center |
|---|---|
| Height | 213 cm (7 ft 0 in) |
| Age | 41 (as of October 2026) |
| Country | Australia |
| College | University of Utah |
| Teams | 4: Milwaukee Bucks, Golden State Warriors, Dallas Mavericks, Cleveland Cavaliers |
| Career span | 2005–2017 |
QUESTIONS
- How tall is Andrew Bogut?
- Andrew Bogut is listed at 213 cm (7 ft 0 in).
- What position does Andrew Bogut play?
- Andrew Bogut plays a center.
- Which teams has Andrew Bogut played for?
- Andrew Bogut's record shows four teams: Milwaukee Bucks, Golden State Warriors, Dallas Mavericks and Cleveland Cavaliers.
- Where did Andrew Bogut go to college?
- Andrew Bogut went to University of Utah.
- How old is Andrew Bogut?
- Andrew Bogut was born on 1984-11-28 and is 41 years old as of October 2026.